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Q.
The molality of $648 \,g$ of pure water is
Solutions
Solution:
Molality $=\frac{\text { no of moles of solute }}{\text { mass of solvent in kg }}$
Molar mass of water $=18 \,g$
Mass of water $=648 \, g$
No of moles of water $=\frac{648}{18}=36 \, mol$
Molality $=\frac{36 \times 1000}{648}=55.5 \, m$