Question

The molality (in $molk{g}^{-1}$ ) of $1$ mole of solute in $50g$ of solvent is

• A. 10
• B. 20
• C. 30
• D. 40

Answer 1

Answer: (B)

Given,

Moles of solute $(n)=1mol$

Mass of solvent $\left(w_A\right)=50g$

$\because$ Molality $(m)=\frac{n\times 1000}{w_A(\text{ in }g)}$

$\therefore m=\frac{1000}{50}=20molk{g}^{-1}$