The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of 14 mV and 6 mV respectively is :

Question

The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of 14 mV and 6 mV respectively is : (A) 1.4 (B) 0.4 (C) 0.2 (D) 0.6

Tardigrade Admin · Accepted Answer

μ= text modulation index =(A max -A min /A max +A min ) =(14-6/14+6)=0.4

Q. The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of $14 mV$ and $6 mV$ respectively is :

1.4

0.4

0.2

0.6

$μ = modulation index = \frac{A _{m a x} - A _{m i n}}{A _{m a x} + A _{m i n}}$
$= \frac{14 - 6}{14 + 6} = 0.4$

Q. The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of 14mV and 6mV respectively is :

1.4

0.4

0.2

0.6

μ= modulation index =Amax​+Amin​Amax​−Amin​​ =14+614−6​=0.4

Q. The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of $14 mV$ and $6 mV$ respectively is :

$μ = modulation index = \frac{A _{m a x} - A _{m i n}}{A _{m a x} + A _{m i n}}$
$= \frac{14 - 6}{14 + 6} = 0.4$