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  4. The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of 14 mV and 6 mV respectively is :

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Q. The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of $14 \,mV$ and $6 \,mV$ respectively is :

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Solution:

$ \mu=\text { modulation index }=\frac{A_{\max }-A_{\min }}{A_{\max }+A_{\min }} $
$ =\frac{14-6}{14+6}=0.4$