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Question
Physics
The minimum phase difference between two SHMs, y1=(1/2) sinω t+(√3/2) cosω t and y2= sinω t+ cosω t is,
Q. The minimum phase difference between two SHMs,
y
1
=
2
1
sin
ω
t
+
2
3
cos
ω
t
and
y
2
=
sin
ω
t
+
cos
ω
t
is,
1298
161
NTA Abhyas
NTA Abhyas 2022
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A
6
π
B
6
−
π
C
12
π
D
12
7
π
Solution:
y
1
=
A
net
sin
ω
t
+
ϕ
1
A
net
=
2
1
2
+
2
3
2
2
=
1
⇒
tan
ϕ
1
=
a
b
=
2
1
2
3
⇒
tan
ϕ
1
=
3
⇒
ϕ
1
=
3
π
y
2
=
A
net
sin
ω
t
+
ϕ
2
⇒
tan
ϕ
2
=
1
1
=
4
5
∘
⇒
ϕ
2
=
4
π
Δ
ϕ
=
ϕ
1
−
ϕ
2
⇒
Δ
ϕ
=
3
π
−
4
π
Δ
ϕ
=
12
π