The minimum magnetic dipole moment of electron in hydrogen atom is

Question

The minimum magnetic dipole moment of electron in hydrogen atom is (A) (eh/2π m) (B) (eh/4π m) (C) (eh/π m) (D) 0

Tardigrade Admin · Accepted Answer

Magnetic dipole moment of electron in an atom is given as M=(n eh/4 π m)=nμ B where, n = number of orbit μB=Bohr Magneton For minimum dipole moment, n = 1 ∴ M=(eh/4 π m)

Q. The minimum magnetic dipole moment of electron in hydrogen atom is

$\frac{e h}{2 πm}$

$\frac{e h}{4 πm}$

$\frac{e h}{πm}$

0

Magnetic dipole moment of electron in an atom is given as
$M = \frac{n e h}{4 πm} = n μ_{B}$
where, n = number of orbit
$μ_{B} =$ Bohr Magneton
For minimum dipole moment, $n = 1$
$∴ M = \frac{e h}{4 πm}$

Q. The minimum magnetic dipole moment of electron in hydrogen atom is

2πmeh​

4πmeh​

πmeh​

0

Magnetic dipole moment of electron in an atom is given as M=4πmneh​=nμB​ where, n = number of orbit μB​=Bohr Magneton For minimum dipole moment, n=1 ∴M=4πmeh​

$\frac{e h}{2 πm}$

$\frac{e h}{4 πm}$

$\frac{e h}{πm}$

Magnetic dipole moment of electron in an atom is given as
$M = \frac{n e h}{4 πm} = n μ_{B}$
where, n = number of orbit
$μ_{B} =$ Bohr Magneton
For minimum dipole moment, $n = 1$
$∴ M = \frac{e h}{4 πm}$