The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is: [Given: The threshold frequency of platinum is 1.3 × 1015 s -1 and .h =6.6 × 10-34 J s .]

Question

The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is: [Given: The threshold frequency of platinum is 1.3 × 1015 s -1 and .h =6.6 × 10-34 J s .] (A) 3.21 × 10-14 J (B) 6.24 × 10-16 J (C) 8.58 × 10-19 J (D) 9.76 × 10-20 J

Tardigrade Admin · Accepted Answer

W = h v =6.6 × 10-34 × 1.3 × 1015 =8.58 × 10-19 J

Q. The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is:
[Given: The threshold frequency of platinum is $1.3$ $\times 1 0^{15} s^{- 1}$ and $h = 6.6 \times 1 0^{- 34} J s .]$

$3.21 \times 1 0^{- 14} J$

$6.24 \times 1 0^{- 16} J$

$8.58 \times 1 0^{- 19} J$

$9.76 \times 1 0^{- 20} J$

$W = h v$
$= 6.6 \times 1 0^{- 34} \times 1.3 \times 1 0^{15}$
$= 8.58 \times 1 0^{- 19} J$

Q. The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is: [Given: The threshold frequency of platinum is 1.3 ×1015s−1 and h=6.6×10−34Js.]

3.21×10−14J

6.24×10−16J

8.58×10−19J

9.76×10−20J