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Q. The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is:
[Given: The threshold frequency of platinum is $1.3$ $\times 10^{15} \,s ^{-1}$ and $\left.h =6.6 \times 10^{-34}\, J s .\right]$

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Solution:

$W = h v $
$=6.6 \times 10^{-34} \times 1.3 \times 10^{15} $
$=8.58 \times 10^{-19}\, J $