Question

The middle term of the progression $4,9,14,\dots .104$ is

• A. 44
• B. 49
• C. 59
• D. 54

Answer 1

Answer: (D)

Given A.P. is $4,9,14,....,104$
Here $a=4$ and $d=5$
$4+(n-1)5=104$
$\Rightarrow n=21$
so middle term is $T_{11}$
$T_{11}=4+10\times 5=54$