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Q. The middle term of the progression $4,9,14, \ldots .104$ is

Sequences and Series

Solution:

Given A.P. is $4, 9, 14, ...., 104$
Here $a = 4 $ and $d = 5$
$4 + (n - 1) 5 = 104$
$ \Rightarrow n = 21$
so middle term is $T_{11}$
$T_{11} = 4 + 10 × 5 = 54 $