Question

The mid point of the interval for which the inequality $x^2-4(\sqrt{x}{)}^2\le 12$ is satisfied, is

• A. 2
• B. 3
• C. 0
• D. 1

Answer 1

Answer: (B)

$x^2-4x-12\le 0$
$x\in [-2,6]\text{ but }x\ge 0$
$\Rightarrow x\in [0,6]$
$\text{ midpoint of interval }=3$