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  4. The mid point of the interval for which the inequality x2-4(√x)2 ≤ 12 is satisfied, is

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Q. The mid point of the interval for which the inequality $x^2-4(\sqrt{x})^2 \leq 12$ is satisfied, is

Complex Numbers and Quadratic Equations

Solution:

$ x^2-4 x-12 \leq 0$
$x \in[-2,6] \text { but } x \geq 0 $
$\Rightarrow x \in[0,6] $
$\text { midpoint of interval }=3$