The maximum velocity to which a proton can be accelerated in a cyclotron of 10 MHz frequency and radius 50 cm is

Question

The maximum velocity to which a proton can be accelerated in a cyclotron of 10 MHz frequency and radius 50 cm is (A)  6.28 × 108 m/s  (B)  3.14 × 108 m/s  (C)  6.28 × 107 m/s  (D)  3.14 × 107 m/s

Tardigrade Admin · Accepted Answer

The motion of proton in magnetic field will be circular ∴ V=2π rf =2×3.14×50×10-2×10×106 =3.14×107 m/s

Q. The maximum velocity to which a proton can be accelerated in a cyclotron of $10 M Hz$ frequency and radius $50 c m$ is

$6.28 \times 1 0^{8} m / s$

$3.14 \times 1 0^{8} m / s$

$6.28 \times 1 0^{7} m / s$

$3.14 \times 1 0^{7} m / s$

The motion of proton in magnetic field will be circular
$∴ V = 2 π r f$
$= 2 \times 3.14 \times 50 \times 1 0^{- 2} \times 10 \times 1 0^{6}$
$= 3.14 \times 1 0^{7} m / s$

Q. The maximum velocity to which a proton can be accelerated in a cyclotron of 10MHz frequency and radius 50cm is

6.28×108m/s

3.14×108m/s

6.28×107m/s

3.14×107m/s