Question

The maximum velocity to which a proton can be accelerated in a cyclotron of $ 10\, MHz $ frequency and radius $ 50\, cm $ is

• A. $ 6.28 \times 10^{8}\,m/s $
• B. $ 3.14 \times 10^{8}\,m/s $
• C. $ 6.28 \times 10^{7}\,m/s $
• D. $ 3.14 \times 10^{7}\,m/s $

Answer 1

Answer: (D)

The motion of proton in magnetic field will be circular
$\therefore V=2\pi rf$
$=2\times3.14\times50\times10^{-2}\times10\times10^{6}$
$=3.14\times10^{7} m/s$