The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7 mm, is 4.4 m/s. The period of oscillation is :

Question

The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7 mm, is 4.4 m/s. The period of oscillation is : (A) 0.01 s (B) 10 s (C) 0.1 s (D) 100 s

Tardigrade Admin · Accepted Answer

The maximum velocity of a particle performing SHM is given by v = A

ω

, where A is the amplitude and

ω

is the angular frequency of oscillation.

∴ 4.4 = (7 \times 1 0^{- 3}) \times 2 π / T

\Rightarrow T = \frac{7 \times 1 0 ^{- 3}}{4.4} \times \frac{2 \times 22}{7} = 0.01 s

Q. The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7 mm, is 4.4 m/s. The period of oscillation is :

0.01 s

10 s

0.1 s

100 s

The maximum velocity of a particle performing SHM is given by v = Aω , where A is the amplitude and ω is the angular frequency of oscillation. ∴4.4=(7×10−3)×2π/T ⇒T=4.47×10−3​×72×22​=0.01s

The maximum velocity of a particle performing SHM is given by v = A $ω$ , where A is the amplitude and $ω$ is the angular frequency of oscillation.
$∴ 4.4 = (7 \times 1 0^{- 3}) \times 2 π / T$
$\Rightarrow T = \frac{7 \times 1 0 ^{- 3}}{4.4} \times \frac{2 \times 22}{7} = 0.01 s$