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  4. The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7 mm, is 4.4 m/s. The period of oscillation is :

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Q. The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7 mm, is 4.4 m/s. The period of oscillation is :

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Solution:

The maximum velocity of a particle performing SHM is given by v = A$\omega$ , where A is the amplitude and $\omega$ is the angular frequency of oscillation.
$\therefore \, \quad 4.4 =\left(7\times10^{-3}\right)\times2\pi/T $
$\Rightarrow \, \quad T=\frac{7\times10^{-3}}{4.4}\times\frac{2\times22}{7}=0.01 s$