The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If two neutrons and two protons combine to form a helium nucleus of mass 4.0015 amu, the B.E of the helium nucleus will be

Question

The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If two neutrons and two protons combine to form a helium nucleus of mass 4.0015 amu, the B.E of the helium nucleus will be (A) 28.4 MeV (B) 20.8 MeV (C) 27.1 MeV (D) 14.2 MeV

Tardigrade Admin · Accepted Answer

BE =[Z Mp+(A-Z) Mn-M] × 931.5 =[(2 × 1.0073)+(2 × 1.0087)-4.0015] × 931.5 , MeV =2.84 MeV

Q. The masses of neutron and proton are $1.0087$ amu and $1.0073$ amu respectively. If two neutrons and two protons combine to form a helium nucleus of mass $4.0015$ amu, the B.E of the helium nucleus will be

28.4 MeV

20.8 MeV

27.1 MeV

14.2 MeV

$BE = [Z M_{p} + (A - Z) M_{n} - M] \times 931.5$
$= [(2 \times 1.0073) + (2 \times 1.0087) - 4.0015] \times 931.5, M e V$
$= 2.84 M e V$

Q. The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If two neutrons and two protons combine to form a helium nucleus of mass 4.0015 amu, the B.E of the helium nucleus will be