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  4. The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If two neutrons and two protons combine to form a helium nucleus of mass 4.0015 amu, the B.E of the helium nucleus will be

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Q. The masses of neutron and proton are $1.0087$ amu and $1.0073$ amu respectively. If two neutrons and two protons combine to form a helium nucleus of mass $4.0015$ amu, the B.E of the helium nucleus will be

Solution:

$BE =\left[Z M_{p}+(A-Z) M_{n}-M\right] \times 931.5$
$=[(2 \times 1.0073)+(2 \times 1.0087)-4.0015] \times 931.5\,, MeV $
$=2.84 \,MeV$