Question

The mass of oxalic acid crystals $(H_2{C}_2{O}_4.2H_{2}O$) required to prepare $50mL$ of a $0.2N$ solution is:

• A. $4.5g$
• B. $6.3g$
• C. $0.63g$
• D. $0.45g$

Answer 1

Answer: (C)

$H_2{C}_2{O}_4.2H_{2}O=2+24+64+36=126$ and Equivalent wt.
$=[\frac{126}{2}]$
$0.2=\frac{W\times 1000}{(\frac{126}{2})\times 50}$
$\therefore W=0.63g$