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  4. The mass of oxalic acid crystals (H2C2O4.2H2O) required to prepare 50 mL of a 0.2 N solution is:

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Q. The mass of oxalic acid crystals $(H_2C_2O_4.2H_2O$) required to prepare $50\, mL$ of a $0.2 \,N$ solution is:

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Solution:

$H_2C_2O_4 . 2H_2O = 2 + 24 + 64 + 36 = 126$ and Equivalent wt.
$ = [\frac{126}{2}]$
$ 0.2 = \frac{W \times 1000}{(\frac{126}{2}) \times 50} $
$\therefore W = 0.63 \,g$