Question

The mass of glucose to be dissolved in 50 g of water to get 0.3 molal solution is

• A. 27 g
• B. 0.27 g
• C. 2.7 g
• D. 5.4 g

Answer 1

Answer: (C)

$m=\frac{w_2\times 1000}{M_2\times w_1\left(ing\right)}$
$0.3=\frac{w_2\times 1000}{180\times 50}$
$w_2=\frac{0.3\times 180\times 50}{1000}=2.7g$