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Q. The mass of glucose to be dissolved in 50 g of water to get 0.3 molal solution is

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Solution:

$m =\frac{w_{2} \times1000}{M_{2} \times w_{1}\left(in g\right)}$
$ 0.3 =\frac{w_{2} \times 1000}{180 \times 50} $
$w_{2} =\frac{0.3 \times 180 \times 50}{1000}=2.7 g$