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Tardigrade
Question
Chemistry
The mass of CaCO3 produced when carbon dioxide is bubbled through 500 mL of 0.5 M Ca(OH)2 will be
Q. The mass of
C
a
C
O
3
produced when carbon dioxide is bubbled through
500
m
L
of
0.5
M
C
a
(
O
H
)
2
will be
5913
185
Some Basic Concepts of Chemistry
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A
10 g
13%
B
20 g
19%
C
50 g
14%
D
25 g
54%
Solution:
C
a
(
O
H
)
2
+
C
O
2
→
C
a
C
O
3
+
H
2
O
C
a
(
O
H
)
2
=
0.5
×
500
×
1
0
−
3
moles
=
0.25
mol
Now
1
mole
C
a
(
O
H
)
2
gives
C
a
C
O
3
=
100
g
0.25
mole
C
a
(
O
H
)
2
gives
C
a
C
O
3
=
0.25
×
100
=
25
g