The mass defect in a nuclear reaction is 0.25 percent. The energy liberated by fusion of one kg matter will be

Question

The mass defect in a nuclear reaction is 0.25 percent. The energy liberated by fusion of one kg matter will be (A)  2.25× 107J  (B)  2.25× 1014J  (C)  6.75× 1010J  (D)  4.5× 107J

Tardigrade Admin · Accepted Answer

: Energy liberated =mc2 =(1kg)× ( 3× 108(m/s) )× (0.25/100)J =(9× 1016× 0.25/100)=2.25× 1014J

Q. The mass defect in a nuclear reaction is 0.25 percent. The energy liberated by fusion of one kg matter will be

$2.25 \times 10^{7} J$

$2.25 \times 10^{14} J$

$6.75 \times 10^{10} J$

$4.5 \times 10^{7} J$

: Energy liberated $= m c^{2}$ $= (1 k g) \times (3 \times 10^{8} \frac{m}{s}) \times \frac{0.25}{100} J$ $= \frac{9 \times 10 ^{16} \times 0.25}{100} = 2.25 \times 10^{14} J$

Q. The mass defect in a nuclear reaction is 0.25 percent. The energy liberated by fusion of one kg matter will be

2.25×107J

2.25×1014J

6.75×1010J

4.5×107J

: Energy liberated =mc2 =(1kg)×(3×108sm​)×1000.25​J =1009×1016×0.25​=2.25×1014J

$2.25 \times 10^{7} J$

$2.25 \times 10^{14} J$

$6.75 \times 10^{10} J$

$4.5 \times 10^{7} J$

: Energy liberated $= m c^{2}$ $= (1 k g) \times (3 \times 10^{8} \frac{m}{s}) \times \frac{0.25}{100} J$ $= \frac{9 \times 10 ^{16} \times 0.25}{100} = 2.25 \times 10^{14} J$