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Q. The mass defect in a nuclear reaction is 0.25 percent. The energy liberated by fusion of one kg matter will be

AMUAMU 1998

Solution:

: Energy liberated $ =m{{c}^{2}} $ $ =(1kg)\times \left( 3\times {{10}^{8}}\frac{m}{s} \right)\times \frac{0.25}{100}J $ $ =\frac{9\times {{10}^{16}}\times 0.25}{100}=2.25\times {{10}^{14}}J $