When C6H5CN reacts with Na/EtOH,C6H5CN undergo for reduction and −C≡N, changes to −CH2−NH2
Thus, the product (P) is
The reaction occurs as follows :
When C6H5CN reacts with (i) HCl (conc. cold) and (ii) Br2/KOH, it gives corresponding primary amine with one C -atom less, as in parent formula (using Hoffmann-Bromamide degradation reaction). Thus, the final product is