The major product of the reaction between CH3CH2ONa and (CH3)3CCl in ethanol is

Question

The major product of the reaction between CH3CH2ONa and (CH3)3CCl in ethanol is (A) CH3 CH2OC(CH3 )3 (B) CH2=C(CH3)2 (C) CH3CH2C(CH3)3 (D) CH3 CH = CHCH3

Tardigrade Admin · Accepted Answer

The major product of the reaction between

C H_{3}, C H_{2} ON a

and

(C H_{3})_{3} CCl

in ethanol is 2-methyl propene.

As

(C H_{3})_{3} CC 1

is tertiary halide and

C H_{3} C H_{2} O^{-} N a^{+}

is a strong base, so elimination is favoured over substitution
reaction and the resultant product is an alkene. This type of elimination is known as (

β

-elimination, where hydrogen is eliminated from

β

-carbon and the halogen is lost from

α

-carbon atom.

Q. The major product of the reaction between $C H_{3} C H_{2} ON a$ and $(C H_{3})_{3} CCl$ in ethanol is

$C H_{3} C H_{2} OC (C H_{3})_{3}$

$C H_{2} = C (C H_{3})_{2}$

$C H_{3} C H_{2} C (C H_{3})_{3}$

$C H_{3} C H = C H C H_{3}$

Q. The major product of the reaction between CH3​CH2​ONa and (CH3​)3​CCl in ethanol is

CH3​CH2​OC(CH3​)3​

CH2​=C(CH3​)2​

CH3​CH2​C(CH3​)3​

CH3​CH=CHCH3​

Q. The major product of the reaction between $C H_{3} C H_{2} ON a$ and $(C H_{3})_{3} CCl$ in ethanol is

$C H_{3} C H_{2} OC (C H_{3})_{3}$

$C H_{2} = C (C H_{3})_{2}$

$C H_{3} C H_{2} C (C H_{3})_{3}$

$C H_{3} C H = C H C H_{3}$