The major product obtained when Br2/Fe is treated with

Question

The major product obtained when Br2/Fe is treated with <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/a0aa758a7f3a44129d2c512646640bab-.png" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

We find that in one benzene ring the key group is > NH which is an activating group while in other the key group is > C = O which is a deactivating group. Hence electrophilic substitution will be governed by the ring having > N-H group. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/d5cbca8e3b6cf52526b8733a3229a8e8-.png" />

Q. The major product obtained when $B r_{2} / F e$ is treated with

We find that in one benzene ring the key group is $> N H$ which is an activating group while in other the key group is $> C = O$ which is a deactivating group. Hence electrophilic substitution will be governed by the ring having $> N - H$ group.

Q. The major product obtained when Br2​/Fe is treated with

We find that in one benzene ring the key group is >NH which is an activating group while in other the key group is >C=O which is a deactivating group. Hence electrophilic substitution will be governed by the ring having >N−H group.

Q. The major product obtained when $B r_{2} / F e$ is treated with

We find that in one benzene ring the key group is $> N H$ which is an activating group while in other the key group is $> C = O$ which is a deactivating group. Hence electrophilic substitution will be governed by the ring having $> N - H$ group.