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Q.
The major product obtained when $Br_2/Fe$ is treated with
Amines
Solution:
We find that in one benzene ring the key group is $\, > NH$ which is an activating group while in other the key group is $> C = O$ which is a deactivating group. Hence electrophilic substitution will be governed by the ring
having $\, > N-H$ group.
