Question

The magnitude of scalar product of two vectors is $8$ and of vector product is $8\sqrt{3}$ . The angle between them is :-

• A. $30^{\circ }$
• B. $60^{\circ }$
• C. $180^{\circ }$
• D. $150^{\circ }$

Answer 1

Answer: (B)

$\overrightarrow{A}\cdot \overrightarrow{B}=ABcos\theta \dots \left(1\right)$
$\left|\overrightarrow{A}\times \overrightarrow{B}\right|=ABsin\theta \dots \left(2\right)$
$\left(2\right)÷\left(1\right)$ $\to tan\theta =\frac{8\sqrt{3}}{8}$
$\theta =60^{\circ }$