Question

The magnitude of scalar product of two vectors is $8$ and of vector product is $8\sqrt{3}$ . The angle between them is :-

• A. $30^\circ $
• B. $60^\circ $
• C. $180^\circ $
• D. $150^\circ $

Answer 1

Answer: (B)

$\overset{ \rightarrow }{A}\cdot \overset{ \rightarrow }{B}=ABcos\theta \ldots \left(1\right)$
$\left|\overset{ \rightarrow }{A} \times \overset{ \rightarrow }{B}\right|=ABsin\theta \ldots \left(2\right)$
$\left(2\right)\div\left(1\right)$ $ \rightarrow tan\theta =\frac{8 \sqrt{3}}{8}$ $$
$\theta =60^\circ $