Tardigrade
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Tardigrade
Question
Physics
The magnitude of maximum acceleration is π times that of maximum velocity of a simple harmonic oscillator. The time period of the oscillator in second is
Q. The magnitude of maximum acceleration is
π
times that of maximum velocity of a simple harmonic oscillator. The time period of the oscillator in second is
2539
201
Punjab PMET
Punjab PMET 2008
Oscillations
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A
4
10%
B
2
76%
C
1
6%
D
0.5
9%
Solution:
Maximum acceleration
=
Maximum velocity
×
π
ie,
ω
2
A
=
πω
A
where
A
is amplitude and
ω
is angular velocity.
⇒
ω
=
π
⇒
T
2
π
=
π
⇒
T
=
2
s