Question

The magnitude of maximum acceleration is $ \pi $ times that of maximum velocity of a simple harmonic oscillator. The time period of the oscillator in second is

• A. 4
• B. 2
• C. 1
• D. 0.5

Answer 1

Answer: (B)

Maximum acceleration $=$ Maximum velocity $\times \pi$
ie, $\omega^{2} A=\pi \omega A$
where $A$ is amplitude and $\omega$ is angular velocity.
$\Rightarrow \omega=\pi$
$\Rightarrow \frac{2 \pi}{T}=\pi$
$\Rightarrow T=2\, s$