The magnifying power of objective of a compound microscope is 7. If magnifying power of microscope is 35, the magnifying power of eye lens will be:

Question

The magnifying power of objective of a compound microscope is 7. If magnifying power of microscope is 35, the magnifying power of eye lens will be: (A) 5 (B) 30 (C) 35 (D) 28

Tardigrade Admin · Accepted Answer

m0=7, M=35, me=? From the formula, M=mo × me 35=7 × me me=5

Q. The magnifying power of objective of a compound microscope is $7$ . If magnifying power of microscope is $35$ , the magnifying power of eye lens will be:

5

30

35

28

$m_{0} = 7, M = 35, m_{e} = ?$
From the formula, $M = m_{o} \times m_{e}$
$35 = 7 \times m_{e}$
$m_{e} = 5$

Q. The magnifying power of objective of a compound microscope is 7. If magnifying power of microscope is 35, the magnifying power of eye lens will be:

5

30

35

28

m0​=7,M=35,me​=? From the formula, M=mo​×me​ 35=7×me​ me​=5

Q. The magnifying power of objective of a compound microscope is $7$ . If magnifying power of microscope is $35$ , the magnifying power of eye lens will be:

$m_{0} = 7, M = 35, m_{e} = ?$
From the formula, $M = m_{o} \times m_{e}$
$35 = 7 \times m_{e}$
$m_{e} = 5$