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Q. The magnifying power of objective of a compound microscope is $7$. If magnifying power of microscope is $35$, the magnifying power of eye lens will be:

Rajasthan PMTRajasthan PMT 2005Ray Optics and Optical Instruments

Solution:

$m_{0}=7,\, M=35,\, m_{e}=?$
From the formula, $M=m_{o} \times m_{e}$
$35=7 \times m_{e}$
$m_{e}=5$