The magnetic moments of two bar magnets of same size are in the ratio 1: 2. When they are placed one over the other with their similar poles together, then their period of oscillation in a magnetic field is 3 s. If one of the magnets is reversed, then the period of oscillation in the same field will be

Question

The magnetic moments of two bar magnets of same size are in the ratio 1: 2. When they are placed one over the other with their similar poles together, then their period of oscillation in a magnetic field is 3 s. If one of the magnets is reversed, then the period of oscillation in the same field will be (A) √3 s (B) 3 √3 s (C) 3 s (D) 6 s

Tardigrade Admin · Accepted Answer

T propto (1/√M) (3/T)=√(M1-M2/M1+M2) ⇒ (3/T)=√(2-1/2+1) ⇒ T=3 √3

$3 s$

$33 s$

$3 s$

$6 s$

$T \propto \frac{1}{M}$
$\frac{3}{T} = \frac{M _{1} - M _{2}}{M _{1} + M _{2}}$
$\Rightarrow \frac{3}{T} = \frac{2 - 1}{2 + 1}$
$\Rightarrow T = 33$

3​s

33​s

3s

6s

T∝M​1​ T3​=M1​+M2​M1​−M2​​​ ⇒T3​=2+12−1​​ ⇒T=33​

$3 s$

$33 s$

$3 s$

$6 s$

$T \propto \frac{1}{M}$
$\frac{3}{T} = \frac{M _{1} - M _{2}}{M _{1} + M _{2}}$
$\Rightarrow \frac{3}{T} = \frac{2 - 1}{2 + 1}$
$\Rightarrow T = 33$