Question

The magnetic field inside a long solenoid of cross-section $15c{m}^2$ is $200T$ . This solenoid crosses a square coil of area $2m^2$ such that the length of the solenoid is parallel to the axis of coil. The magnetic flux linked through the square coil is $xWb$ , then what is the value of $10x$ ?

Answer 1

Answer: 3

Magnetic field due to the solenoid is along its length so $\theta =0^{\circ }$
$\varphi =\overrightarrow{B}\cdot \overrightarrow{A}$
$=200\times 15\times 10^{-4}$
$=0.3Wb$