Question

The magnetic field inside a long solenoid of cross-section $15cm^{2}$ is $200T$ . This solenoid crosses a square coil of area $2m^{2}$ such that the length of the solenoid is parallel to the axis of coil. The magnetic flux linked through the square coil is $xWb$ , then what is the value of $10x$ ?

Answer 1

Magnetic field due to the solenoid is along its length so $\theta =0^\circ $
$\phi=\overset{ \rightarrow }{B}\cdot \overset{ \rightarrow }{A}$
$=200\times 15\times 10^{- 4}$
$=0.3Wb$