The liquid arms of an U-tube is shown in figure below. The shaded part represents the mercury (specific gravity 13.6) and other liquid is water. If the difference between height of mercury in either column is 2 cm, then height of water column is

Question

The liquid arms of an U-tube is shown in figure below. The shaded part represents the mercury (specific gravity 13.6) and other liquid is water. If the difference between height of mercury in either column is 2 cm, then height of water column is (A) 27 cm (B) 23 cm (C) 25 cm (D) 29 cm

Tardigrade Admin · Accepted Answer

Suppose, the atmospheric pressure is p0. Pressure at A=p0+h(1000 textkg textm-3)g Pressure at B=p0+h(0.02 textm)(13600 textkg textm-3)g These pressures, at A and B are equal because points are on the some horizontal level. Thus, h=0.02× 13.6m = 0.27 m or 27 cm

Q. The liquid arms of an U-tube is shown in figure below.
The shaded part represents the mercury (specific gravity 13.6) and other liquid is water. If the difference between height of mercury in either column is 2 cm, then height of water column is

27 cm

23 cm

25 cm

29 cm

Suppose, the atmospheric pressure is $p_{0} .$ Pressure at $A = p_{0} + h (1000 kg m^{- 3}) g$ Pressure at $B = p_{0} + h (0.02 m) (13600 kg m^{- 3}) g$ These pressures, at A and B are equal because points are on the some horizontal level. Thus, $h = 0.02 \times 13.6 m$ = 0.27 m or 27 cm

Q. The liquid arms of an U-tube is shown in figure below. The shaded part represents the mercury (specific gravity 13.6) and other liquid is water. If the difference between height of mercury in either column is 2 cm, then height of water column is