The line y=x is a tangent to the curve y=p x2+q x+ r at the point x=1. If the curve passes through the point (-1,0) then the value of (p +r/q) is

Question

The line y=x is a tangent to the curve y=p x2+q x+ r at the point x=1. If the curve passes through the point (-1,0) then the value of (p +r/q) is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

[Hint: p=(1/4) ; q=(1/2) ; r=(1/4) ∴ (p +r/q)=1

Q. The line $y = x$ is a tangent to the curve $y = p x^{2} + q x + r$ at the point $x = 1.$ If the curve passes through the point $(- 1, 0)$ then the value of $\frac{p + r}{q}$ is

[Hint: $p = \frac{1}{4}; q = \frac{1}{2}; r = \frac{1}{4}$
$∴ \frac{p + r}{q} = 1$

Q. The line y=x is a tangent to the curve y=px2+qx+r at the point x=1. If the curve passes through the point (−1,0) then the value of qp+r​ is

[Hint: p=41​;q=21​;r=41​ ∴qp+r​=1

Q. The line $y = x$ is a tangent to the curve $y = p x^{2} + q x + r$ at the point $x = 1.$ If the curve passes through the point $(- 1, 0)$ then the value of $\frac{p + r}{q}$ is

[Hint: $p = \frac{1}{4}; q = \frac{1}{2}; r = \frac{1}{4}$
$∴ \frac{p + r}{q} = 1$