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Q. The line $y=x$ is a tangent to the curve $y=p x^{2}+q x+ r$ at the point $x=1.$ If the curve passes through the point $(-1,0)$ then the value of $\frac{p +r}{q}$ is

Application of Derivatives

Solution:

[Hint: $p=\frac{1}{4} ; q=\frac{1}{2} ; r=\frac{1}{4}$
$\therefore \frac{p +r}{q}=1$