The line (x-1/3) = (y-1/-1) = (z+1/0) and (x-4/2) = (y+0/0) = (z+1/3)

Question

The line (x-1/3) = (y-1/-1) = (z+1/0) and (x-4/2) = (y+0/0) = (z+1/3)  (A) do not intersect (B) intersect at (4, 1, -2) (C) intersect at (4, 0, -1) (D) intersect at (1, 1, -1)

Tardigrade Admin · Accepted Answer

Correct answer is (c) intersect at (4, 0, -1)

Q. The line 3x−1​=−1y−1​=0z+1​ and 2x−4​=0y+0​=3z+1​

do not intersect

intersect at (4, 1, -2)

intersect at (4, 0, -1)

intersect at (1, 1, -1)

Correct answer is (c) intersect at (4, 0, -1)

Q. The line $\frac{x - 1}{3} = \frac{y - 1}{- 1} = \frac{z + 1}{0}$ and $\frac{x - 4}{2} = \frac{y + 0}{0} = \frac{z + 1}{3}$