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  4. The line (x-1/3) = (y-1/-1) = (z+1/0) and (x-4/2) = (y+0/0) = (z+1/3)

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Q. The line $\frac{x-1}{3} = \frac{y-1}{-1} = \frac{z+1}{0}$ and $ \frac{x-4}{2} = \frac{y+0}{0} = \frac{z+1}{3} $

Introduction to Three Dimensional Geometry

Solution:

Correct answer is (c) intersect at (4, 0, -1)