Question

The length of the common chord of the ellipse $\frac{(x+1{)}^2}{9}+\frac{(y-2{)}^2}{4}=1$ and the circle $x-1^2+y-2^2=1$ is

• A. 0
• B. $\bar{3}$
• C. 4
• D. 5

Answer 1

Answer: (A)

Given : ellipse equation : $÷(x+1{)}^{2}9+÷(y-2{)}^{2}4=1$
Circle equation : $(x-1{)}^2+(y-2{)}^2=1$
$\therefore$ center of ellipse $=(-1,2)$
$a=3,b=2$
$\therefore$ length of major axis is $6$
$\therefore$ length of minor is $4$
$\Rightarrow$ center of circle is $(1,2$ with radius $r=1)$
$\Rightarrow$ so, wecanseeindiagramthatthetwoareasdoesnotintersectortoucheachlengthiso
$\Rightarrow$ Hence, The length of common chord of the ellipse and circle is Zero(o).