The least integer satisfying (396/10)-(19-x/10)

Question

The least integer satisfying (396/10)-(19-x/10) < (376/10)-(19-9x/10) is (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

Inequation is (396/10)-(19-x/10) < (376/10)-(19-9 x/10) ⇒ 396-(19-x) < 376-(19-9 x) ⇒ 377+x < 357+9 x ⇒ 20 < 8 x ⇒ x > (20/8) ⇒ x > 2 ⋅ 5 Least integer is x=3.

Q. The least integer satisfying
$\frac{396}{10} - \frac{19 - x}{10} < \frac{376}{10} - \frac{19 - 9 x}{10}$ is

1

2

3

4

5

Inequation is
$\frac{396}{10} - \frac{19 - x}{10} < \frac{376}{10} - \frac{19 - 9 x}{10}$
$\Rightarrow 396 - (19 - x) < 376 - (19 - 9 x)$
$\Rightarrow 377 + x < 357 + 9 x \Rightarrow 20 < 8 x$
$\Rightarrow x > \frac{20}{8} \Rightarrow x > 2 \cdot 5$
Least integer is $x = 3$ .

Q. The least integer satisfying 10396​−1019−x​<10376​−1019−9x​ is

1

2

3

4

5

Inequation is 10396​−1019−x​<10376​−1019−9x​ ⇒396−(19−x)<376−(19−9x) ⇒377+x<357+9x⇒20<8x ⇒x>820​⇒x>2⋅5 Least integer is x=3.

Q. The least integer satisfying
$\frac{396}{10} - \frac{19 - x}{10} < \frac{376}{10} - \frac{19 - 9 x}{10}$ is

Inequation is
$\frac{396}{10} - \frac{19 - x}{10} < \frac{376}{10} - \frac{19 - 9 x}{10}$
$\Rightarrow 396 - (19 - x) < 376 - (19 - 9 x)$
$\Rightarrow 377 + x < 357 + 9 x \Rightarrow 20 < 8 x$
$\Rightarrow x > \frac{20}{8} \Rightarrow x > 2 \cdot 5$
Least integer is $x = 3$ .