Question

The least integer satisfying
$\frac{396}{10}-\frac{19-x}{10} < \frac{376}{10}-\frac{19-9x}{10}$ is

• A. 1
• B. 2
• C. 3
• D. 4
• E. 5

Answer 1

Answer: (C)

Inequation is
$\frac{396}{10}-\frac{19-x}{10} < \frac{376}{10}-\frac{19-9 x}{10} $
$\Rightarrow 396-(19-x) < 376-(19-9 x) $
$\Rightarrow 377+x < 357+9 x \Rightarrow 20 < 8 x $
$\Rightarrow x > \frac{20}{8} \Rightarrow x > 2 \cdot 5$
Least integer is $x=3$.