The knee voltage of a p-n junction diode is 0.8 V and the with of the depletion layer is 2 μ m, the electric field in the depletion layer is

Question

The knee voltage of a p-n junction diode is 0.8 V and the with of the depletion layer is 2 μ m, the electric field in the depletion layer is (A) 4 MV/m (B) 0.4 MV/m (C) 4 kV/m (D) 0.4 kV/m

Tardigrade Admin · Accepted Answer

E=(Δ V/Δ r)=(0.8/2 × 10-6) =0.4 MV / m

Q. The knee voltage of a p-n junction diode is 0.8 V and the with of the depletion layer is 2 $μ m$ , the electric field in the depletion layer is

4 MV/m

0.4 MV/m

4 kV/m

0.4 kV/m

$E = \frac{Δ V}{Δ r} = \frac{0.8}{2 \times 1 0 ^{- 6}}$
$= 0.4 M V / m$

Q. The knee voltage of a p-n junction diode is 0.8 V and the with of the depletion layer is 2 μm, the electric field in the depletion layer is