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Q. The knee voltage of a p-n junction diode is 0.8 V and the with of the depletion layer is 2 $\mu m$, the electric field in the depletion layer is

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

$E=\frac{\Delta V}{\Delta r}=\frac{0.8}{2 \times 10^{-6}}$
$=0.4 \,MV / m$