The insulation of air vanishes when the electric field is 5 × 105 V / m. The maximum charge that can be given to a sphere of radius 3 m is approximately

Question

The insulation of air vanishes when the electric field is 5 × 105 V / m. The maximum charge that can be given to a sphere of radius 3 m is approximately (A) 5 μ C (B) 500 μ C (C) 10 μ C (D) 1 μ C

Tardigrade Admin · Accepted Answer

E =( Kq / r 2) 5 × 105=(9 × 109 × q /(3)2) (5 × 105 × 9/9 × 109)= q ⇒ q =5 × 10-4 C =500 μ C

Q. The insulation of air vanishes when the electric field is $5 \times 1 0^{5} V / m$ . The maximum charge that can be given to a sphere of radius $3 m$ is approximately

$5 μ C$

$500 μ C$

$10 μ C$

$1 μ C$

$E = \frac{K q}{r ^{2}}$
$5 \times 1 0^{5} = \frac{9 \times 1 0 ^{9} \times q}{( 3 ) ^{2}}$
$\frac{5 \times 1 0 ^{5} \times 9}{9 \times 1 0 ^{9}} = q$
$\Rightarrow q = 5 \times 1 0^{- 4} C = 500 μ C$

Q. The insulation of air vanishes when the electric field is 5×105V/m. The maximum charge that can be given to a sphere of radius 3m is approximately

5μC

500μC

10μC

1μC