The initial nucleus of uranium series is 92U238 and the final nucleus is 82Pb206. When uranium decays to lead how many α and β particles are produced ?

Question

The initial nucleus of uranium series is 92U238 and the final nucleus is 82Pb206. When uranium decays to lead how many α and β particles are produced ? (A) 6,8 (B) 8,6 (C) 4,3 (D) 3,4

Tardigrade Admin · Accepted Answer

No. of α-particles: (238 - 206/4) = (32/4) = 8 and No. of β--particles: 82 - (92 - 8 × 2) = 6

Q. The initial nucleus of uranium series is $_{92} U^{238}$ and the final nucleus is $_{82} P b^{206}$ . When uranium decays to lead how many $α$ and $β$ particles are produced ?

6,8

8,6

4,3

3,4

No. of $α$ -particles : $\frac{238 - 206}{4} = \frac{32}{4} = 8$ and No. of $β$ --particles : 82 - (92 - 8 $\times$ 2) = 6

Q. The initial nucleus of uranium series is 92​U238 and the final nucleus is 82​Pb206. When uranium decays to lead how many α and β particles are produced ?

6,8

8,6

4,3

3,4

No. of α-particles : 4238−206​=432​=8 and No. of β--particles : 82 - (92 - 8 × 2) = 6

Q. The initial nucleus of uranium series is $_{92} U^{238}$ and the final nucleus is $_{82} P b^{206}$ . When uranium decays to lead how many $α$ and $β$ particles are produced ?

No. of $α$ -particles : $\frac{238 - 206}{4} = \frac{32}{4} = 8$ and No. of $β$ --particles : 82 - (92 - 8 $\times$ 2) = 6